If the average of 12 consecutive odd integers is 328 what is the least of these integers?

Let x be the smallest odd integer, x + 2 the second integer, x + 4 the third odd integer, etc. Set up an average equation with all of the integers.
(x+x+2+x+4+x+6+x+8+x+10+x+12+x+14+x+16+x+18+x+20+x+22)/12= 328
(12x + 132)/12 = 328
Multiply both sides by 12
12x + 132 = 3936
Subtract 132 from both sides.
12x = 3804
Divide both sides by 12
x = 317

Answer Link

jainveenamrata jainveenamrata · Answer 2 · 2022-08-23T12:58:16+02:00

The 12 consecutive odd integers will be 317, 319, 321, 323, 325, 327, 329, 331, 333, 335, 337, and 339.

What is Algebra?

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

If the average of 12 consecutive odd integers is 328.

Let the 12 consecutive odd number be x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16, x + 18, x + 20, and x + 22. Then we have

(x+x+2+x+4+x+6+x+8+x+10+x+12+x+14+x+16+x+18+x+20+x+22) / 12 = 328

12x + 132 = 3936

12x = 3804

x = 317

Then the 12 consecutive odd integers will be 317, 319, 321, 323, 325, 327, 329, 331, 333, 335, 337, and 339.

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