contestada

A gas in a rigid container at 25°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 atm. What is the new temperature of the gas?

Respuesta :

mergl
T1=298.15K, P1=0.96 atm, P2=1.25 atm, T2=?
(P1/T1)=(P2/T2)
(0.96)/(298.15)=(1.25)/(T2)
(1.25)/((.96)/(298.15))=T2
T2=388.2161458K
T2=115.0661 degrees Celsius
kenmyna

The new temperature  of the gas is  388.02 k  or 115.02°c

 calculation

The  new temperature  is calculated  using Gay Lussac's   formula

That is P₁/T₁ = P₂/T₂

where;

P₁  = 0.96 atm

T₁ = 25°c into kelvin   = 25 +273  =298 k

P₂= 1.25 atm

T₂ =  ?  k

make T₂ the subject of the formula

T₂ = P₂T₁/P₁

 = (1.25 atm x 298 k) / 0.96 atm  =  388.02 K   or  388.02 -273 =115.02°c