what combination of integers can be used to generate the pythagorean triple (8,15,17)
A. x=2 y=2
B. x=3 y=2
C. x=4 y=3
D. x=4 y=1

Respuesta :

Answer:

D. x=4, y=1

Step-by-step explanation:

We know that,

The Pythagorean triples are generated by x, y and [tex](2xy,x^2-y^2,x^2+y^2)[/tex], where x,y > 0 and are integers.

To generate the triple (8,15,17), we have the system,

[tex]2xy=8[/tex]            ...........(1)

[tex]x^2-y^2=15[/tex]    ............(2)

[tex]x^2+y^2=17[/tex]    ............(3)

Adding (2) and (3), we get,

[tex]2x^2=32[/tex]

i.e. [tex]x^2=16[/tex]

i.e. [tex]x=\pm 4[/tex]

Substitute the value of x in (1), we get,

[tex]2\times 4y=8[/tex]

i.e. [tex]8y=8[/tex]

i.e. [tex]y=\pm 1[/tex]

So, we get the integers,

x = 4, y= 1 and x= -4, y= 1.

Thus, according to the options, the integers which generate the triples are x = 4, y= 1.