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Joaquin has created a small treasure map that is in the shape of a square. He decides to make a larger version of the map, and on this new map he increases each side by 6 inches. The area of this larger version of the map is 121 square inches. What are the dimensions of his original, smaller map? 5 inches by 5 inches 8 inches by 8 inches 11 inches by 11 inches 17 inches by 17 inches

Respuesta :

WojtekR
a - side of small map
a+6 - side of larger map
(a+6)² - area of larger map

(a+6)² = 121
(a+6)² = 11²    |√(...)
a+6 = 11    |-6
a+6-6 = 11-6
a = 5

Answer A. 5 inches by 5 inches

The dimensions of the original map was; A: 5 Inches by 5 Inches

What are the dimensions of the map?

Let the each side length of the small map be x

We are told that he increased each side length on the new map by 6 inches. Thus;

Each side length of new map = x + 6

Thus;

Area of larger map version = (x + 6)²

This new map has an area of 121 sq. in. Thus;

(x + 6)² = 121

(x + 6)² = 11²

x + 6 = √11²

x + 6 = 11

x = 11 - 6

x = 5 in

Read more about map dimensions at; https://brainly.com/question/8998277

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