2x- 3y=9

5x+3y=12

How would i solve this? I dont understand this and i really need help with it!Also I have to graph the anwsers afterward on a graph, so i really need the help. I appreciate it:)

[tex]\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ + \ \ ------- \\ 7x=21 \ \ /: 7\\ \\x=\frac{21}{3}\\ \\ x=3 \\ \\2x- 3y=9[/tex]

[tex]2*3-3y=9\\ \\6-3y =9\\ \\-3y=9-6\\ \\-3y=3 \ \ / :(-3)\\ \\x=-1\\ \\ \begin{cases} x=3\\y= -1 \end{cases}[/tex]

[tex]graph\\ \\\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ \\ \begin{cases} - 3y=-2x+9\ \ /:(-3) \\ 3y=-5x+12 \ \ /:3 \end{cases}\\ \\ \begin{cases} y= \frac{2}{3}x-3 \\ y=-\frac{5}{3}x+4 \end{cases}[/tex]

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2x- 3y=9 5x+3y=12 How would i solve this? I dont understand this and i really need help with it!Also I have to graph the anwsers afterward on a graph, so i really need the help. I appreciate it:)

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2x- 3y=9

5x+3y=12

How would i solve this? I dont understand this and i really need help with it!Also I have to graph the anwsers afterward on a graph, so i really need the help. I appreciate it:)