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The axis of symmetry for the function f(x) = –2x2 + 4x + 1 is the line x = 1. Where is the vertex of the function located? (0, 1) (1, 3) (1, 7) (2, 1)?????

Respuesta :

ghanami
hello :
-2x²+4x+1= -2(x-1)²+b
find : b
-2x²+4x+1 = -2(x²-2x+1)+b
             -2x²+4x+1  = -2x² +4x -2+b
 -2+b = 1
b = 3
-2x²+4x+1= -2(x-1)²+3

 the vertex of the function located is :  (1, 3)  
ankitprmr2

The coordinate of the vertex is ( 1, 3 ).

Given the function.

[tex]f(x) = -2x^2 + 4x + 1[/tex]

The axis of symmetry for the function is [tex]x=1[/tex].

The vertex of any curve is always located at the symmetrical axis. The intersection point of the symmetrical axis and the function leads to the vertex of the function.

Therefore, find the intersection point of the function and the symmetrical axis.

[tex]f(x) = -2x^2 + 4x + 1[/tex]

[tex]x=1[/tex]

Put x = 1 in the function.

[tex]f(1) = -2(1)^2 + 4 \times 1 + 1\\=-2+4+1\\=3[/tex]

Thus, the coordinate of the vertex is ( 1, 3 ).

To know more about the vertex, please refer to the link:

https://brainly.com/question/4239808

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