The figure below shows the net of a triangular pyramid. The given height is rounded to the nearest hundredth. If all the triangles are equilateral, what is the surface area of the pyramid in square centimeters? HEIGHT: 4.33 cm BASE: 5 cm. *The net shows 4 triangles but I think one of them is the base of the triangle.*

Respuesta :

Answer: 43.3 square inches

Step-by-step explanation:

Formula for Triangle: A = bh/2

Key:

* = multiple

/ = divide

Fill in the formula with what you know:

A = bh/2

A = 5 * 4.33 / 2

A= 21.65 / 2 = 10.825 square inches

However, 10.825 is not our answer. 10.825 is the area of only one triangle. Since all four of the triangles are congruent (or the same) we can:

Add: 10.825 + 10.825 + 10.825 + 10.825 = 43.3 square inches

OR

Multiple: 10.825 * 4 = 43.3 square inches

Thus, the surface area of the pyramid is 43.3 square inches.

The net of a triangular pyramid shows four equilateral triangle, which has the surface area of the pyramid 43.3 square centimetre.

What is equilateral triangle?

A equilateral triangle is the triangle in which all the three sides are of equal length in measure.

It is given that, the height of the triangular pyramid is 4.33 cm.

Base of the triangular pyramid is 5 cm.

The image of the figure shown below.

Area of a triangle is half of the product of base to height. Thus,

[tex]A=\dfrac{1}{2}\times5\times4.33\\A=10.825[/tex]

Now the surface of the pyramid is the 4 times the area of each triangle. Thus,

[tex]A_s=4\times10.8.25\\A_s=43.3\rm cm^2[/tex]

Thus the surface area of the pyramid 43.3 square centimetre.

Learn more about the equilateral triangle here;

https://brainly.com/question/1099318

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