Answer:
Option B is correct
[tex]\pm 11[/tex]
Step-by-step explanation:
Given the equation:-
[tex]2x^2 = 242[/tex]
Divide both sides by 2 we have;
[tex]x^2 = 121[/tex]
Taking square root both sides we have;
[tex]\sqrt[2]{x^2} =\pm \sqrt{121}[/tex]
We can write 121 as:
[tex]121 = 11^2[/tex]
then;
[tex]\sqrt[2]{x^2} =\pm \sqrt{(11)^2}[/tex]
Simplify:
[tex]x = \pm 11[/tex]
Therefore, the solution for the given equations is, [tex]\pm 11[/tex]
