Marlene lives in a building where half the residents live on the first floor and half live on the second floor. She wants to estimate the probability that, out of 3 randomly selected residents, 1 or 2 live on the first floor.

She uses a coin to conduct a simulation, by letting H represent someone living on the first floor and T represent someone living on the second floor and then flipping the coin three times. She repeats this process for a total of 15 trials. The results are shown in the table.

Estimated probability that 1 or 2 of 3 randomly selected residents live on the first floor: ________

A.1/2
B.1/6
C.5/6
D.5/12

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Respuesta :

mathgenius14 mathgenius14 · Answer 1 · 2017-05-18T17:43:20+02:00

The correct answer is: 5/6

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PratikshaS PratikshaS · Answer 2 · 2022-06-26T18:38:04+02:00

The probability that 1 or 2 of 3 randomly selected residents live on the first floor is [tex]\bold{\frac{5}{6}}[/tex]

The correct answer is option (C)

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

P(A) = n(A)/n(S)

where, n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.

For given question,

From given table,

n(S) = 12

Suppose, event A: 1 or 2 of 3 randomly selected residents live on the first floor.

⇒ A = {HTT, HHT, HTT, THH, HHT, THT, HTH, THH, HHH, HHH}

⇒ n(A) = 10

Using formula of probability,

[tex]P(A)=\frac{n(A)}{n(S)}\\\\ P(A)=\frac{10}{12}\\\\ P(A)=\frac{5}{6}[/tex]

Therefore, the probability that 1 or 2 of 3 randomly selected residents live on the first floor is [tex]\bold{\frac{5}{6}}[/tex]

The correct answer is option (C)

Learn more about probability here:

brainly.com/question/11234923

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