Respuesta :
hello :
a reasonable domain for this function is : ]0 ; + ∞[
because : x > 0 and x+4 > 0 .... f(x) = x(x+4) ... length ×width
a reasonable domain for this function is : ]0 ; + ∞[
because : x > 0 and x+4 > 0 .... f(x) = x(x+4) ... length ×width
Answer:
All values of x greater than 0.
Step-by-step explanation:
Let x represent width of rectangle.
We have been given that the length of rectangle is 4 units greater than its width. So the length of rectangle would be [tex]x+4[/tex].
[tex]\text{Area of rectangle=\text{Width}\times \text{Length}[/tex]
[tex]\text{Area of rectangle=x(x+4)[/tex]
[tex]\text{Area of rectangle=x^2+4x[/tex]
The domain of a function is all real values of independent variable that the function can take on.
Since our given function represents the area of rectangle, where x represents width of rectangle, so the value of x should be a non zero and non-negative number.
Therefore, the domain of our given function would be [tex]x>0\text{ that is}(0,\infty)[/tex]