The option for this question will be 270.
Arc of circle
The part of the circumference of a circle is called the Arc of the circle.
Given
[tex]\angle TOC=128^{o} \\
\angle TOB= 90^{o} [/tex]
How to calculate arc TCB?
[tex]\angle TOC + \angle COD =180^{o} \\
128^{o} + \angle COD= 180^{o} \\
\angle COD = 52^{o} [/tex]
Similarly
[tex]\angle TOC + \angle BOD =180^{o} \\
90^{o} + \angle BOD= 180^{o} \\
\angle COD = 90^{o} [/tex]
Then [tex]\angle TCB [/tex] will be
[tex]\angle TCB = \angle TOC + \angle COD + \angle DOB\\
\angle TCB = 128^{o} + 52^{o} + 90^{o} \\
\angle TCB = 270^{o} [/tex]
Hence, the option for this question will be 270.
More about the arc of the circle link is given below.
https://brainly.com/question/1577784