In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.

Create and graph a function to model the population, y , (in thousands), x years after 2000.
In complete sentences, interpret the relationship between the rate of change of the function and its graph.
Predict the population of the city in the year 2012.

b) As the years go by, the population increases. The years (X), and population (Y) both increase together. The graph shows that when the years increase the population increases.

c) In 2012, which would be 12 years later, I predict the population would be around 743,232 people.

Answer Link

MrRoyal MrRoyal · Answer 2 · 2022-01-31T18:32:09+01:00

The equation that represents the function is [tex]y = 600000(1.018)^x[/tex], and the population of the country in 2012 is 743232

The given parameters are:

Initial Population = 600,000

Rate = 1.8%

Population are represented by exponential functions

An exponential function is represented as:

[tex]y = a(1 + r)^x[/tex]

So, we have:

[tex]y = 600000(1 + 1.8\%)^x[/tex]

Evaluate the sum

[tex]y = 600000(1.018)^x[/tex]

See attachment for the graph of the function

In 2012, x = 12.

So, we have:

[tex]y = 600000(1.018)^{12[/tex]

[tex]y = 743232[/tex]

Hence, the population of the country in 2012 is 743232

Read more about exponential functions at:

https://brainly.com/question/11464095