Respuesta :

irspow
-12x-2y≤-42  add 12x to both sides

-2y≤12x-42 divide both sides by -2 (and reverse direction of inequality because of division by a negative)

y≥-6x+21

Answer:

The inequality in slope-intercept form is given by:

                 [tex]y\geq -6x+21[/tex]

Step-by-step explanation:

We know that a equation in the slope-intercept form is given by:

         [tex]y=mx+c[/tex]

where m is the slope and c is the y-intercept form of the line.

Now, if we have to write the inequality in slope-intercept form then the equality sign is replaced by the inequality sign.

Here we have the inequality as follows:

[tex]-12x-2y\leq -42[/tex]

Now, we add 12x on both the side of the inequality to obtain:

[tex]-2y\leq -42+12x[/tex]

Now, we multiply both side of the inequality by -1 to get:

[tex]2y\geq -(-42+12x)\\\\i.e.\\\\2y\geq 42-12x\\\\i.e.\\\\2y\geq -12x+42[/tex]

Now, we divide both side of the inequality by  2 to obtain:

[tex]y\geq -6x+21[/tex]

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