A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. If the basin is completely filled with water, how much water will it hold? Round the answer to the nearest tenth of a foot.

The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h where "h" represents the height and "r" for the radius. Hence, in the given problem we have h=2ft and r=diameter/2.
r=5/2
r=2.5 ft
Solving for the volume:
V=3.1416*2.5²*2
V=39.27 cubic feet
If 1 cubic feet can hold 7.5 gallons, therefore the cylindrical basin can hold
#gallon=39.27*(7.5/1)
#gallon=294.525 gallons

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raphealnwobi raphealnwobi · Answer 2 · 2022-01-21T13:22:56+01:00

The basin when completely filled with water can hold 39.3 ft³of water

Volume

Volume shows the amount of space enclosed by a closed surface. It is the amount of space that an object occupies, or that is enclosed within a container.

The volume of a cylinder = πr²h

where r is the radius, h is the height.

r = diameter / 2 = 5 ft./2 = 2.5 ft., h = 2 feet, hence:

Volume = π(2.5)²(2) = 39.3 ft³

The basin when completely filled with water can hold 39.3 ft³of water

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