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Leslie rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 11?
A. 2/36
B. 3/36
C. 4/36
D. 5/36

Respuesta :

irspow
The only way to get an 11 is with a 5 and a 6 so the probability of rolling a sum of 11 is:

(2/6)(1/6)=2/36

Answer:

im not 100% but i think the answer is option a

Step-by-step explanation:

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