Respuesta :
Recall that the secant function is the reciprocal function to the cosine function.
Also, recall that sin²x + cos²x = 1 and 1 - sin²x = cos²x
Thus, we can rewrite the equation as:
[tex]\frac{tan(x) \cdot cos^{2}(x)}{cos(x)} = x[/tex]
[tex]tan(x) \cdot cos(x) = x[/tex]
[tex]\frac{sin(x) \cdot cos(x)}{cos(x)} = x[/tex]
[tex]sin(x) = x[/tex]
There's only one point at which sin(x) = x, and that's at x = 0.
Thus, x = 0 is the only solution.
Also, recall that sin²x + cos²x = 1 and 1 - sin²x = cos²x
Thus, we can rewrite the equation as:
[tex]\frac{tan(x) \cdot cos^{2}(x)}{cos(x)} = x[/tex]
[tex]tan(x) \cdot cos(x) = x[/tex]
[tex]\frac{sin(x) \cdot cos(x)}{cos(x)} = x[/tex]
[tex]sin(x) = x[/tex]
There's only one point at which sin(x) = x, and that's at x = 0.
Thus, x = 0 is the only solution.
Answer: sin
Step-by-step explanation:
Just took this on A Pex You’re welcome. I got it correct when I put sin in the blank before the x
