Aileen deposited money into an account in which interest is compounded semiannually at a rate of 2.1% how much did she deposit if the total amount in her account after 3 years was 3952.08?

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Answer:

$3712.

Step-by-step explanation:

We have been given that Aileen deposited money into an account compounded semiannually at a rate of 2.1%.

To find the principal amount we will use compound interest formula.

[tex]A=P(1+\frac{r}{n})^{nT}[/tex], where,

A= Amount after T years,

P =Principal amount,

r = Interest rate in decimal form,

n = Number of times interest is compounded per year,

T = Time in years.

Let us convert our given interest rate in decimal form.

[tex]2.1\%=\frac{2.1}{100}=0.021[/tex]

Upon substituting our given values in above formula we will get,

[tex]3952.08=P(1+\frac{0.021}{2})^{2*3}[/tex]

[tex]3952.08=P(1+0.0105)^{6}[/tex]

[tex]3952.08=P(1.0105)^{6}[/tex]

[tex]3952.08=P*1.0646770855930465[/tex]

Let us divide both sides of our equation by 1.0646770855930465.

[tex]\frac{3952.08}{1.0646770855930465}=\frac{P*1.0646770855930465}{1.0646770855930465}[/tex]

[tex]3711.9987397856=P[/tex]

[tex]P\approx 3712[/tex]

Therefore, Aileen deposited approximately $3712 in her account.

Answer:

3714

Step-by-step explanation:

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