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1) A negative point charge of 2.0 × 10^–6 C experiences a force of 0.060 N from another source charge. What is the strength of the electric field, and how does its direction compare with the force?

A) 3.0 × 10^4 N/C, same


B) 3.0 × 10^4 N/C, opposite <<<<


C) 1.2 × 10^3 N/C, same


D) 1.5 × 10^4 N/C, opposite


2) Two point charges of +2.50 × 10^–5 C and –2.50 × 10^–5 C are separated by 0.50 m. Which of the following describes the force between them?

A) 45 N, attractive

B) 23 N, attractive

C) 90 N, attractive <<<<

D) 90 N, repulsive


3) Two parallel plates have an electric potential difference of 20.0 V. If the electric field between them has a strength of 1.0 × 10^3 N/C, then how far apart are the plates?

A) 1.0 cm

B) 2.0 cm <<<<<<<

C) 10.0 cm

D) 5.0 cm


4) An electric field measured near a point charge of 3.00 × 10^–6 C has a strength of 1.50 × 10^5 N/C. How far is the point from the source charge?

A) 0.42 m

B) 0.36 m <<<<<

C) 0.095 m

D) 0.30 m

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1) The strength of the electric field 3*10^4 opposite

2) Force between two charges 23 N

3) The distance between the plates will be 2 cm

4) The distance of the point from the source 0.42 m

What is coulombs law?

According to Coulomb's law: The magnitude of each of the electric forces with which two point-at-rest charges interact is directly proportional to the product of the magnitude of both charges

And inversely proportional to the square of the distance that separates them and has the direction of the line that joins them.

The formula will be given as:

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

1) Given thta charge =2*10^-6 and force=0.060 N

The electric strength formula is

[tex]E=\dfrac{F}{q}[/tex]

[tex]E=\dfrac{0.06}{2\times 10^{-6}}\\[/tex]

[tex]E=3\times 10^{4} \dfrac{N}{C}[/tex]

2) The force between two charges q=2.5*10^-5 and distance 0.5m

[tex]F=\dfrac{8.988\times 10^9\times 2.5\times 10^{-5}\times 2.5\times 10^{-5}}{0.5^2}[/tex]

[tex]F=23\ N[/tex]

3) The distance between parallel plates

[tex]V=Ed[/tex]

[tex]d=\dfrac{V}{E}=\dfrac{20}{1\times 10^3}}=2 cm[/tex]

4) Distance of the point charge from the source charge.

[tex]E=\dfrac{Eq}{r^2}[/tex]

[tex]r^2=\dfrac{8.98\times 10^9\times 3\times 10^{-6}}{1.5\times 10^5}[/tex]

[tex]r=0.42\ m[/tex]

So the above are the given answers.

To know more about coulomb's law follow

https://brainly.com/question/66110