Suppose that a solution containing 3.50 grams of sodium phosphate (Na3PO4) is mixed with a solution containing 6.40 grams of barium nitrate (Ba(NO3)2). Calculate the theoretical yield of barium phosphate (Ba3(PO4)2) during this reaction.
2Na3PO4 + 3Ba(NO3)2 Ba3(PO4)2 + 6NaNO3
and the reaction 2 Na3PO4 + 3 Ba(NO3)2 ----> Ba3(PO4)2 + 6 NaNO3
Convert the masses to moles using molar masses of N3PO4 and Ba(NO3)2 Next, determine the limiting reactant by using stoichiometry: moles Na3PO4 (1 / 2) = moles Ba3PO4 moles Ba(NO3)2 (1 /3) = moles Ba3PO4
The lower amount of moles will be maximum and the reactant is limiting Convert moles to mass and divide it by the mass of the limiting reactant to get the yield.
