≡ We know that:
⇔ Consider the first integer is [tex]a[/tex]
⇔ So, the next integer is [tex](a+1)[/tex]
≡ Solution:
⇒ [tex](a).(a+1)=56[/tex]
⇒ [tex]a^{2}+a=56[/tex]
⇒ [tex]a^{2}+a-56=0[/tex]
⇒ [tex](a+8)(a-7)=0[/tex]
⇒ [tex]a_{1}=-8[/tex]║[tex]a_{2}=7[/tex]
⇔ For [tex]a=-8[/tex]
⇒ the next integer is [tex](a+1)=-8+1=-7[/tex]
⇔ For [tex]a=7[/tex]
⇒ the next integer is [tex](a+1)=(7+1)=8[/tex]
∴ So, there are 2 options [[tex]\boxed{-8}[/tex] and [tex]\boxed{-7}[/tex]] or [[tex]\boxed{7}[/tex] and [tex]\boxed{8}[/tex]]
