Which linear inequality is represented by the graph?
y ≤ x – 1.3
y ≤ x –
y ≥ x –
y ≥ x – 1.3

First we look for the equation of the line.
The generic equation is:
[tex] y = mx + b
[/tex]
Where,
m: slope of the line.
b: cutting point with vertical axis.
The slope of the linear is given by:
[tex] m = \frac{-0.3 - (-1.3)}{3 - 0}
[/tex]
[tex] m = \frac{-0.3 + 1.3}{3}
[/tex]
[tex] m =\frac{1}{3}
[/tex]
The point of cut with the vertical axis we observe it in the graph:
[tex] b = -1.3
[/tex]
Then, the equation of the line is:
[tex] y =\frac{1}{3} x - 1.3
[/tex]
To find the correct inequality, we evaluate points that belong to the solution in the given equation.
[tex] y \leq \frac{1}{3} x - 1.3
[/tex]
For (5, 0) we have:
[tex] 0 \leq \frac{1}{3} 5 - 1.3
[/tex]
[tex] 0 \leq 1.7 - 1.3 [/tex]
[tex] 0 \leq 0.4 [/tex]
We observe that the inequality is met
Answer:
A linear inequality that is represented by the graph is:
[tex] y \leq \frac{1}{3} x - 1.3
[/tex]
The linear equality represented by the graph is [tex]\boxed{y\leqslant\frac{1}{3}x-1.3}[/tex].
Further explanation:
It is given that a line passes through points [tex]\left({0,-\,1.3}\right)[/tex] and [tex]\left({3,-\,0.3}\right)[/tex] as shown below in Figure 1.
The slope of a line passes through points [tex]\left({{x_1},{y_1}}\right)[/tex] and [tex]\left({{x_2},{y_2}}\right)[/tex] is calculated as follows:
[tex]m=\frac{{{y_2}-{y_1}}}{{{x_2}-{x_1}}}[/tex] .......(1)
Here, the slope of a line is denoted as [tex]m[/tex] and points are [tex]\left({{x_1},{y_1}}\right)[/tex] and [tex]\left({{x_2},{y_2}}\right)[/tex] .
Substitute [tex]0[/tex] for [tex]{x_1}[/tex] , [tex]-1.3[/tex] for [tex]{y_1}[/tex] , [tex]3[/tex] for [tex]{x_2}[/tex] and [tex]-0.3[/tex] for [tex]{y_2}[/tex] in equation (1) to obtain the slope of a line that passes through points [tex]\left({0,-\,1.3}\right)[/tex] and [tex]\left({3,-\,0.3}\right)[/tex] .
[tex]\begin{aligned}m&=\frac{{-0.3-\left({-1.3}\right)}}{{3-0}}\\&=\frac{1}{3}\\\end{aligned}[/tex]
Therefore, the slope is [tex]\frac{1}{3}[/tex] .
The point-slope form of the equation of a line with slope [tex]m[/tex] passes through point [tex]\left({{x_1},{y_1}}\right)[/tex] is represented as follows:
[tex]y-{y_1}=m\left({x-{x_1}}\right)[/tex] ......(2)
Substitute [tex]0[/tex] for [tex]{x_1}[/tex] , [tex]-1.3[/tex] for [tex]{y_1}[/tex] and [tex]\frac{1}{3}[/tex] for [tex]m[/tex] in equation (2) to obtain the equation of line.
[tex]\begin{aligned}y-\left({-1.3}\right)&=\frac{1}{3}\left({x-0}\right)\\y+1.3&=\frac{1}{3}x\\y&=\frac{1}{3}x-1.3\\\end{aligned}[/tex]
Therefore, the value of [tex]y[/tex] is [tex]\frac{1}{3}x-1.3[/tex] .
Since the shaded part in Figure 1 is below the equation of line [tex]y=\frac{1}{3}x-1.3[/tex] , therefore, less than sign is also used with “is equal to”.
Thus, the linear inequality is [tex]y\leqslant\frac{1}{3}x-1.3[/tex] .
Thus, the linear equality represented by the graph is [tex]\boxed{y\leqslant\frac{1}{3}x-1.3}[/tex] .
Learn more:
1. Which classification best describes the following system of equations? https://brainly.com/question/9045597
2. What is the value of [tex]x[/tex] in the equation [tex]x-y=30[/tex] when [tex]y=15[/tex] ? https://brainly.com/question/3965451
3. What are the values of x? https://brainly.com/question/2093003
Answer Details:
Grade: Junior High School
Subject: Mathematics
Chapter: Coordinate Geometry
Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, inequality.