Respuesta :

First we look for the equation of the line.

The generic equation is:

[tex] y = mx + b
[/tex]

Where,

m: slope of the line.

b: cutting point with vertical axis.

The slope of the linear is given by:

[tex] m = \frac{-0.3 - (-1.3)}{3 - 0}
[/tex]

[tex] m = \frac{-0.3 + 1.3}{3}
[/tex]

[tex] m =\frac{1}{3}
[/tex]

The point of cut with the vertical axis we observe it in the graph:

[tex] b = -1.3
[/tex]

Then, the equation of the line is:

[tex] y =\frac{1}{3} x - 1.3
[/tex]

To find the correct inequality, we evaluate points that belong to the solution in the given equation.

[tex] y \leq \frac{1}{3} x - 1.3
[/tex]

For (5, 0) we have:

[tex] 0 \leq \frac{1}{3} 5 - 1.3
[/tex]

[tex] 0 \leq 1.7 - 1.3 [/tex]

[tex] 0 \leq 0.4 [/tex]

We observe that the inequality is met

Answer:

A linear inequality that is represented by the graph is:

[tex] y \leq \frac{1}{3} x - 1.3
[/tex]

The linear equality represented by the graph is [tex]\boxed{y\leqslant\frac{1}{3}x-1.3}[/tex].

Further explanation:

It is given that a line passes through points [tex]\left({0,-\,1.3}\right)[/tex] and  [tex]\left({3,-\,0.3}\right)[/tex] as shown below in Figure 1.

The slope of a line passes through points [tex]\left({{x_1},{y_1}}\right)[/tex] and [tex]\left({{x_2},{y_2}}\right)[/tex] is calculated as follows:

[tex]m=\frac{{{y_2}-{y_1}}}{{{x_2}-{x_1}}}[/tex]                             .......(1)

Here, the slope of a line is denoted as [tex]m[/tex] and points are [tex]\left({{x_1},{y_1}}\right)[/tex] and [tex]\left({{x_2},{y_2}}\right)[/tex] .

Substitute [tex]0[/tex]  for [tex]{x_1}[/tex] , [tex]-1.3[/tex]  for [tex]{y_1}[/tex] ,   [tex]3[/tex] for [tex]{x_2}[/tex]  and [tex]-0.3[/tex]  for [tex]{y_2}[/tex]  in equation (1) to obtain the slope of a line that passes through points [tex]\left({0,-\,1.3}\right)[/tex]  and [tex]\left({3,-\,0.3}\right)[/tex] .

[tex]\begin{aligned}m&=\frac{{-0.3-\left({-1.3}\right)}}{{3-0}}\\&=\frac{1}{3}\\\end{aligned}[/tex]

Therefore, the slope is [tex]\frac{1}{3}[/tex] .

The point-slope form of the equation of a line with slope [tex]m[/tex]  passes through point [tex]\left({{x_1},{y_1}}\right)[/tex] is represented as follows:

[tex]y-{y_1}=m\left({x-{x_1}}\right)[/tex]                                   ......(2)

Substitute [tex]0[/tex]  for [tex]{x_1}[/tex] , [tex]-1.3[/tex]  for [tex]{y_1}[/tex]  and [tex]\frac{1}{3}[/tex]  for [tex]m[/tex]  in equation (2) to obtain the equation of line.

[tex]\begin{aligned}y-\left({-1.3}\right)&=\frac{1}{3}\left({x-0}\right)\\y+1.3&=\frac{1}{3}x\\y&=\frac{1}{3}x-1.3\\\end{aligned}[/tex]

Therefore, the value of [tex]y[/tex]  is [tex]\frac{1}{3}x-1.3[/tex] .

Since the shaded part in Figure 1 is below the equation of line [tex]y=\frac{1}{3}x-1.3[/tex] , therefore, less than sign is also used with “is equal to”.

Thus, the linear inequality is [tex]y\leqslant\frac{1}{3}x-1.3[/tex] .

Thus, the linear equality represented by the graph is [tex]\boxed{y\leqslant\frac{1}{3}x-1.3}[/tex] .

Learn more:

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2. What is the value of [tex]x[/tex]  in the equation [tex]x-y=30[/tex] when [tex]y=15[/tex] ? https://brainly.com/question/3965451

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Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, inequality.

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