JoDoggy
contestada

Which quadratic equation defines the function that has zeros at −1/12 and 1/4
A) -48x2 - 8x - 1 = 0
B) 48x2 - 8x - 1 = 0
C) 48x2 + 8x - 1 = 0

Respuesta :

[tex]\bf \begin{cases} x=-\cfrac{1}{12}\implies 12x=-1\implies &12x+1=0\\\\ x=\cfrac{1}{4}\implies 4x=1\implies &4x-1=0 \end{cases}\\\\ -----------------------------[/tex]

[tex]\bf (12x+1)(4x-1)=\stackrel{original~polynomial}{0}\implies \stackrel{FOIL}{48x^2-8x-1=y}[/tex]

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