Respuesta :
area=1/2bh
solveifn for b
times 2 both sides and divide by h
2area/h=b
given
area=2/5
h=6/5
(2*2/5)/(6/5)=b
(4/5)/(6/5)=b
(4/5)(5/6)=b
(20/30)=b
2/3=b
base=2/3ft
solveifn for b
times 2 both sides and divide by h
2area/h=b
given
area=2/5
h=6/5
(2*2/5)/(6/5)=b
(4/5)/(6/5)=b
(4/5)(5/6)=b
(20/30)=b
2/3=b
base=2/3ft
Answer:
[tex]\frac{2}{3}[/tex] feet.
Step-by-step explanation:
We have been given that area of a triangle is [tex]\frac{2}{5}\text{ ft}^2[/tex]. We are asked to find the length of the base of the triangle.
[tex]A=\frac{1}{2}bh[/tex], where,
A= Area of the triangle,
b = Base of the triangle,
h = height of the triangle.
Upon substituting our given values in are of triangle formula we will get,
[tex]\frac{2}{5}=\frac{1}{2}*b*\frac{6}{5}[/tex]
[tex]\frac{2}{5}=b*\frac{3}{5}[/tex]
Upon multiplying both sides of our equation by 5/3 we will get,
[tex]\frac{2}{5}*\frac{5}{3}=b*\frac{3}{5}*\frac{5}{3}[/tex]
[tex]\frac{2}{3}=b[/tex]
Therefore, the length of the base of our given triangle will be [tex]\frac{2}{3}[/tex] feet.