Answer : The force of interaction between them is 1.35 N
Explanation :
Charge 1 [tex]q_1=7.1\times 10^{-6}\ C[/tex]
Charge 2, [tex]q_2=6.9\times 10^{-6}\ C[/tex]
Distance between charges, [tex]d=5.7\times 10^{-1}\ m[/tex]
The force of interaction between them is given by using Coulomb's law. It is written as :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
k is electrostatic constant
[tex]F=9\times 10^9\times \dfrac{7.1\times 10^{-6}\ C\times 6.9\times 10^{-6}\ C}{(5.7\times 10^{-1}\ m)^2}[/tex]
[tex]F=1.35\ N[/tex]
Hence, this is the required solution.
