Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.

29 and 31
39 and 41
49 and 51

Respuesta :

i think the answer is 29 and 31

2 consecutive odd numbers....x and x + 2

3/7x + 1/3(x + 2) = 38
3/7x + 1/3x + 2/3 = 38
3/7x + 1/3x = 38 - 2/3....multiply by common denominator of 21
9x + 7x = 798 -14
16x = 784
x = 784 / 16
x = 49

x + 2 = 49 + 2 = 51

ur numbers are 49 and 51