Respuesta :
Answer:The correct answer is option D.
Explanation:
Amount of dose given to patient = [tex]N_o=2g[/tex]
Half life of Barium-131 =[tex]t_{\frac{1}{2}}=10 days[/tex]
Amount of barium-131 left after 10 days.
t = 10 days
[tex]\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{10 days}= 0.0693 day^{-1}[/tex]
[tex]N=N_o\times e^{-\lambda t}[/tex]
[tex]\log N=\log N_o -\frac{\lambda t}{2.303}[/tex]
[tex]\log N=\log [2]-\frac{0.0693 day^{-1}\times 10 days}{2.303}[/tex]
[tex]N=0.999 g\approx 1 g[/tex]
Hence, correct answer is option D.
