Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?




Respuesta :

the base of cylinder b has an are of 9 unites

Answer:

The factor is [tex]\frac{3}{2}[/tex].

Step-by-step explanation:

Given : Cylinders A and B are similar solids.

The base of cylinder A has a circumference of  [tex]4\pi[/tex] units.

The base of cylinder B has an area of  [tex]9\pi[/tex] units.

To find :  The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

Solution :

Let x be the factor.

So, according to question,

[tex]\text{Dimension of cylinder A}\times x = \text{Dimension of cylinder B}[/tex]   ........[1]

The dimension refer here are radius of both cylinders.

In cylinder A,

Circumference of base is [tex]4\pi[/tex] units.

Circumference of base of cylinder is [tex]C=2\pi r[/tex]

[tex]4\pi=2\pi r[/tex]

[tex]r=2[/tex]

The dimension of cylinder A is r=2

In cylinder B,

Area of cylinder is [tex]9\pi[/tex] units.

Area of base of cylinder is [tex]A=\pi r^2[/tex]

[tex]9 \pi=\pi r^2[/tex]

[tex]r^2=9[/tex]

[tex]r=3[/tex]

The dimension of cylinder B is r=3

Substitute in [1]

[tex]2x=3[/tex]

[tex]x=\frac{3}{2}[/tex]

Therefore, The factor is [tex]\frac{3}{2}[/tex].