Answer:
The slope of BC is -7/2.
Step-by-step explanation:
Givens
ABCD is a rectangle.
AB [tex]\parallel[/tex] CD
BC [tex]\parallel[/tex] AD.
[tex]m_{AB} =\frac{2}{7}[/tex]
We know that [tex]AB \perp BC[/tex] and [tex]CD \perp AD[/tex], by definition of rectangle.
Additionally, [tex]m_{AB} \times m_{BC}=-1[/tex], by condition of perpendicularity.
Replacing, we have
[tex]\frac{2}{7} \times m_{BC}=-1\\ m_{BC}=-\frac{7}{2}[/tex]
Therefore, the slope of BC is -7/2.
