Answer:
[tex]11\ ft[/tex]
Step-by-step explanation:
we have
[tex]4\frac{1}{2}\ ft[/tex]
[tex]4\ ft[/tex]
[tex]2\frac{1}{2}\ ft[/tex]
we know that
The length of all three tables when pushed end to end is the sum of the three lengths
Convert mixed number to an improper fraction
[tex]4\frac{1}{2}\ ft=\frac{4*2+1}{2}=\frac{9}{2}\ ft[/tex]
[tex]2\frac{1}{2}\ ft=\frac{2*2+1}{2}=\frac{5}{2}\ ft[/tex]
therefore
[tex]\frac{9}{2}\ ft+4\ ft+\frac{5}{2}\ ft[/tex]
Rewrite [tex]4\ ft[/tex] as [tex]\frac{8}{2}\ ft[/tex]
so
[tex]\frac{9}{2}\ ft+\frac{8}{2}\ ft+\frac{5}{2}\ ft=\frac{22}{2}\ ft=11\ ft[/tex]
