Answer:
The factored form of the equation [tex]6x^{2}+2x-8=0[/tex] is [tex]2(3x+4)(x-1)=0[/tex]
Step-by-step explanation:
Given equation is [tex]6x^{2}+2x-8=0[/tex]
Above equation can be written as
[tex]6x^{2}+8x-6x-8=0[/tex]
=>[tex]2x(3x+4)-2(3x+4)=0[/tex]
Taking (3x+4) common from the above equation, we get
[tex](3x+4)(2x-2)=0[/tex]
Again taking 2 common out of (2x-2) we get
=>[tex]2(3x+4)(x-1)=0[/tex]
Thus the factored form of the given equation is [tex]2(3x+4)(x-1)=0[/tex]
