Respuesta :
squar root both sides
z=+/-0.8
if you are having trouble wit the decimals
0.64=64/100
so if you squar root both sides
remember [tex] \sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} } [/tex] so
[tex] \sqrt{ \frac{64}{100} } = \frac{ \sqrt{64} }{ \sqrt{100} } = \frac{ \sqrt{8} }{ \sqrt{10} } [/tex]=+/-0.8
z=+/-0.8
if you are having trouble wit the decimals
0.64=64/100
so if you squar root both sides
remember [tex] \sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} } [/tex] so
[tex] \sqrt{ \frac{64}{100} } = \frac{ \sqrt{64} }{ \sqrt{100} } = \frac{ \sqrt{8} }{ \sqrt{10} } [/tex]=+/-0.8
Answer:
[tex]z = \pm 0.8[/tex]
Step-by-step explanation:
Use exponent rules:
[tex]\sqrt[n]{x^n} = x[/tex]
Solve the equation:
[tex]z^2 = 0.64[/tex]
Taking square root both sides we have;
[tex]\sqrt{z^2} = \pm \sqrt{0.64}[/tex]
Apply the exponent rule we have;
[tex]z = \pm \sqrt{0.64}[/tex]
We can write 0.64 as:
[tex]0.64 = 0.8 \cdot 0.8 = (0.8)^2[/tex]
then;
[tex]z = \pm \sqrt{(0.8)^2}[/tex]
Simplify:
[tex]z = \pm 0.8[/tex]