Answer with Explanation:
f(x)= Linear Function
g(x)= Rational Function
⇒Let , f(x)=a x +b
f(3)= 7
3 a + b=7------------(1)
f(4)=5
5 a + b=5--------(2)
⇒Equation(2) - Equation (1)
2 a= -2
Dividing both side by 2, we get
a = -1
Putting the value of 'a' in equation (1)
3 × (-1)+ b=7
b=7+3
b=10
So,Linear function = -x +10
⇒Let, Rational Function
[tex]g(x)=\frac{1}{px+q}\\\\g(3)=\frac{1}{3p+q}=5.6\\\\3.\rightarrow 3 p +q=\frac{1}{5.6}\\\\g(4)=6.7\\\\4.\rightarrow 4 p+q=\frac{1}{6.7}[/tex]
Equation 4 - Equation 3
[tex]p=\frac{1}{6.7}-\frac{1}{5.6}\\\\ p=\frac{-1.1}{37.52}\\\\p=\frac{-11}{375.2}[/tex]
Substituting the value of 'p' in equation 4
[tex]q=\frac{10}{6.7 \times 5.6}=\frac{100}{375.2}[/tex]
So, Rational Function
[tex]=\frac{375.2}{-11 x+100}[/tex]
⇒Now, we have to check whether there is a solution to the equation
f(x)=g(x), between x=3 and x=4.
[tex]\frac{375.2}{-11 x+100}=-x+10\\\\\rightarrow 11 x^2-110 x-100 x+1000=375.2\\\\\rightarrow 11 x^2-210 x+624.80=0\\\\x=\frac{210 \pm\sqrt{44100 -44 \times 624.80}}{22}\\\\ax^2+bx+c=0\\\\x=\frac{-b\pm\Sqrt {b^2-4 ac}}{2a}\\\\x=\frac{210\pm\sqrt{44100- 27491.20}}{22}\\\\x=\frac{210 \pm 128.875}{22}\\\\x=\frac{338.875}{22} \\\\x=\frac{81.125}{22}\\\\x=15.40 \text{and} \\\\x=3.6875[/tex]
Yes, there is a solution to the equation ƒ(x)=g(x) between x=3 and x=4 which is, x=3.6875.
