Use energy conservation, since no energy is lost it must be constant.
E = 0.5mv² + mgh
At release the velocity v = 0 and the height is h.
E = 0 + mgh
At impact the height h = 0 and the velocity is v.
E = 0.5mv² + 0
Since the energy E is conserved:
0.5mv² = mgh
the mass m cancels and the equation becomes:
0.5v² = gh
h = 0.5v²/g
when g = 9.81 and v = 22:
h = 24,66
