Respuesta :
[tex]x( \theta) = \frac{v_0^{2} sin(2\theta)}{g} \\ \\ \frac{dx}{d \theta} = - \frac{ 2v_0^{2} }{g} cos(2 \theta) = 0 \\ \\ 2 \theta = \frac{ \pi}{2} \\ \\ \theta = \frac{ \pi}{4} \\ \\ x_m_a_x = x( \frac{ \pi}{4} )= \frac{v_0^{2} sin( \frac{ \pi}{2} )}{g}[/tex]