a news paper carrier has 10.30 in change. he has two more quarters than dimes but three times as many nickles as quarters. how many coins of each type does he have
A) .05n + .10d + .25 q = 10.30 B) d +2 = q C) n = 3q Substituting equations B and C into A A) .05*3q + .10(q-2) + .25 q = 10.30 A) .15q + .1q -.2 + .25q = 10.30 A) .50q = 10.50 21 quarters
