Respuesta :
(16+12+15+13+17+p)/(5+1)[tex] \geq [/tex]15
(73+p)/6[tex] \geq [/tex]15
73+p[tex] \geq [/tex]90
p[tex] \geq [/tex]17
(73+p)/6[tex] \geq [/tex]15
73+p[tex] \geq [/tex]90
p[tex] \geq [/tex]17
You will need to find the average of the 6 games, then you will use the greater than or equal sign, since you have to have "at least" that score to average 15.
(16 + 12 + 15 + 13 + 17 + x) / 6 ≥ 15
(16 + 12 + 15 + 13 + 17 + x) / 6 ≥ 15