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A thin 14.7 m long copper rod in a uniform magnetic field has a mass of 49.0 g. When the rod carries a current of 0.317 A, it floats in the magnetic field. What is the field strength of the magnetic field?

Respuesta :

[tex]F_B = ILBsin \theta[/tex]

F force
I current
L length of wire in magnetic field
B magnetic field strength
θ angle between wire and magnetic field

if θ = 90°

[tex]B = \frac{F_B}{IL} \\ \\ F_B = F_G = mg \\ \\ B = \frac{mg}{IL} = \frac{0.049* 9.81 }{0.317*14.7} [/tex]

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