Respuesta :
well, assuming is "simple interest" rate
[tex]\bf \qquad \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$200\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ t=years\to &10 \end{cases}[/tex]
[tex]\bf \qquad \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$200\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ t=years\to &10 \end{cases}[/tex]
Answer:
Part A:
As any particular interest is not mentioned, we will calculate the simple interest formula.
[tex]SI=p\times r\times t[/tex]
Now as per given scenario, here p is s.
t is n
So, we can calculate interest as:
[tex]I=s\times r\times n[/tex]
And [tex]b=s+I[/tex]
Part B:
Here p = 200
r = 4% or 0.04
t = 10 years
So, interest is [tex]200\times0.04\times10=80[/tex] dollars
And amount after 10 years is = [tex]200+80=280[/tex] dollars
