knuckles8437
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The force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the charge on particle A is
7.2 × 10-8 coulombs, what is the charge of particle B?
(k = 9.0 × 109 newton·meters2/coulomb2)

A 2.4 × 10-2 coulombs

B 4.6 × 10-11 coulombs

C 5.2 × 10-11 coulombs

D 7.2 × 10-8 coulombs

Respuesta :

[tex]F_e = \frac{q_1q_2k}{ r^{2} } [/tex]

[tex]q_1 = \frac{F_e r^{2} }{q_2k} [/tex]

[tex]q_1 = 4,6 * 10^{-11} [/tex]

I hope.


nutanraj654

Option B 4.6 × 10-11 coulombs.

Fe = q1q2k/r2

q1 = fer2/q2k

q1 = 1.6 x 10-11

What is newton meter per coulomb?

Newton Per Coulomb ( N/C) is a unit in the category of Electric field strength. It is also known as newtons/coulomb.

Learn more about newton·meters2 at

https://brainly.com/question/1068333

#SPJ2

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