Respuesta :
Appreciation rate = 1.2% = 0.012
Let it take n years
300000^0.012n = 350000
taking log
0.012n * log(300000) = log(350000)
0.012n * 5.4771 = 5.5440
0.0657252 n = 5.5440
n = 84.35 years
2017 + 84.35 = 2101.35
It will be worth $350,000 in 2101
Let it take n years
300000^0.012n = 350000
taking log
0.012n * log(300000) = log(350000)
0.012n * 5.4771 = 5.5440
0.0657252 n = 5.5440
n = 84.35 years
2017 + 84.35 = 2101.35
It will be worth $350,000 in 2101
A=p(1+r)^t
350000=300000(1+0.012)^t
350000/300000=(1.012)^t
Log(350000/300000)=t*log(1.012)
T=log(350000/300000)/log(1.012)
T=12.92 round =13 years
2017+13==2,030
350000=300000(1+0.012)^t
350000/300000=(1.012)^t
Log(350000/300000)=t*log(1.012)
T=log(350000/300000)/log(1.012)
T=12.92 round =13 years
2017+13==2,030