contestada

Use substitution to solve.

2x² = 5 + y
4y = -20 + 8x²
Solve the first equation for y and substitute it into the second equation. The resulting equation is

Respuesta :

konrad509
[tex]2x^2= 5 + y\\ 4y = -20 + 8x^2 \\\\ y=2x^2-5\\ 4y = -20 + 8x^2 \\\\ 4(2x^2-5)=-20+8x^2\\ 8x^2-20=8x^2-20\\ 0=0[/tex]

The equations are identical. They're satisfied by any pair [tex](x,2x^2-5)[/tex] where [tex]x\in\mathbb{R}[/tex].
mommiesnootnoot

Answer:

Solve the first equation for y and substitute it into the second equation. The resulting equation is

✔ 8x² - 20 = -20 + 8x²

.

The system has

✔ infinitely many solutions

.

Step-by-step explanation:

Otras preguntas