Respuesta :
24+3x≥100
remember you can do anything to an equaiton as long as you do it to bot hsides
24+3x≥100
minus 24 both sides
3x≥76
divide both sies by 3
x≥25.333333
round up since yo can't do something 0.333 times
26
26 more times
remember you can do anything to an equaiton as long as you do it to bot hsides
24+3x≥100
minus 24 both sides
3x≥76
divide both sies by 3
x≥25.333333
round up since yo can't do something 0.333 times
26
26 more times
The correct answer is:
At least 26 times.
Explanation:
The inequality is given to us: 24+3x ≥ 100.
To solve this, we first cancel 24 by subtracting it from both sides:
24+3x-24 ≥ 100-24
3x ≥ 76
Next we cancel 3 by dividing both sides by 3:
3x/3 ≥ 76/3
x ≥ 25.333
We cannot have 0.3 times, so we round up to the next whole number, 26.
(The reason we round up when mathematically we would "round down" is because 25 would not give us quite enough marbles, 26 does.)