The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (??) units, and the area of the triangle is (??) square units. (Hint: Use the Pythagorean theorem.)
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5 then find area A=1/2bh 1/2(3*4) 6
