Answer: [tex]m\angle{B}=132^{\circ}[/tex]
Step-by-step explanation:
In the given picture, we have given cyclic Quadrilateral ABCD which is inscribed in this circle.
We know that in cyclic quadrilateral the sum of the opposite angles is equals to [tex]180^{\circ}[/tex]
According to the given picture we have ,
[tex]m\angle{D}+m\angle{B}=180^{\circ}\\\\\Rightarrow x+(3x-12)=180\\\\\Rightarrow x+3x-12=180\\\\\Rightarrow 4x=180+12\\\\\Rightarrow 4x=192\\\\\Rightarrow x=48[/tex]
Therefore, [tex]m\angle{B}=(3(48)-12)^{\circ}=132^{\circ}[/tex]