Respuesta :
Alright, this is an easy one!
So we are trying to get rid of the y value so the first equation has -3y. The second equation has 2y. What values would make these equal.
A.) 2*-3y = -6y and 3 * 2y = 6y.
Now take -6y + 6y and that gives you 0.
Thus, the answer is A.) Multiply the first equation by 2 and the second equation by 3.
So we are trying to get rid of the y value so the first equation has -3y. The second equation has 2y. What values would make these equal.
A.) 2*-3y = -6y and 3 * 2y = 6y.
Now take -6y + 6y and that gives you 0.
Thus, the answer is A.) Multiply the first equation by 2 and the second equation by 3.
Answer:
Option (a) is correct.
To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.
Step-by-step explanation:
Given system of equations, 2x - 3y = 3 and 5x + 2y = 17
We have to form a linear combination to eliminate the variable y for this given system.
Consider the given system
2x - 3y = 3 .......(1)
5x + 2y = 17 ........(2)
Since, we have to eliminate y from the given system.
This can be done when we make the coefficient of y in both equation same.
So, we Multiply the first equation by 2 and the second equation by 3.
Thus, we get,
2x - 3y = 3 .......(1) × 2
⇒ 4x - 6y = 6 .....(3 )
5x + 2y = 17 ........(2) × 3
⇒ 15x + 6y = 51 .....(4)
Now , add (3) and (4) , we get,
4x - 6y +(15x + 6y) = 6 + 51
On simplify, we get
20x = 57
Which is completely in terms of x only and y is eliminated.
Thus, To form a linear combination to eliminate the variable y for this given system multiply the first equation by 2 and the second equation by 3.
Option (a) is correct.
