Answer:
The electrical force that each charge exerts on the other one will be same .
Explanation:
Given that,
Two point charges, q₁ and q₂, are separated by a distance r.
The electric force will be
[tex]F = \dfrac{kq_{1}q_{2}}{r^2}[/tex]
If the magnitudes of both charges are doubled and their separation is also doubled.
The new electric force will be
[tex]F' = \dfrac{k\times2\times q_{1}\times2\times q_{2}}{(2r)^2}[/tex]
[tex]F'=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
[tex]F'=F[/tex]
Therefore, We can say that the new electric force F' will be same as the electric force F.
Hence, The electrical force that each charge exerts on the other one will be same .
The electrical force that each charge exerts on the other one will remain the same
From Coulomb's law,
F = Kq₁q₂ / r²
F = (9×10⁹ × q × q) / r²
F = (9×10⁹ × q²)/ r²
From Coulomb's law,
F = Kq₁q₂ / r²
Fₙ = (9×10⁹ × 2q × 2q) / (2r)²
Fₙ = (9×10⁹ × 2q × 2q) / (2r)²
Fₙ = (9×10⁹ × 4q²) / 4r²
Cancel 4
Fₙ = (9×10⁹ × q²) / r²
SUMMARY
From the above calculation, we can see that the initial and new force is the same.
Thus, we can conclude that the force exerted by each charge will remain the same.
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