Answer: 1) 849 K
2) [tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Explanation:
Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
[tex]V_1[/tex]= initial volume = 1.50 L
[tex]V_2[/tex]= final volume = 4.50 L
[tex]T_1[/tex]= initial temperature =[tex]10^0C=(10+273)K=283K[/tex]
[tex]T_2[/tex]= final temperature =?
[tex]\frac{1.50 }{283}=\frac{4.50}{T_2}[/tex]
[tex]T_2=849K[/tex]
