Respuesta :
to find the discriminant we use b^2 - 4ac
equation of 4x^2 - 3x + 3 = 0
a b c
-3^2 - 4 (4)(3) = -39
if b^2 - 4ac < 0, there are 2 complex roots or...no real roots...in this case imaginary.
equation of 4x^2 - 3x + 3 = 0
a b c
-3^2 - 4 (4)(3) = -39
if b^2 - 4ac < 0, there are 2 complex roots or...no real roots...in this case imaginary.
Answer:
roots are imaginary
Step-by-step explanation:
[tex]4x^2 - 3x + 3 = 0[/tex]
Formula to find discriminant is [tex]b^2-4ac[/tex]
Given equation is in the form of ax^2+bx+c=0
a=4, b=-3, c=3
Plug in all the values in the discriminant formula
[tex]b^2-4ac=(-3)^2-4(4)(3)=-39[/tex]
When discriminant >0, the roots are real
when discriminant <0 then roots are imaginary
we got discriminant =-39 that is less than 0, so roots are imaginary