Find the area of the figure shown in the diagram to the nearest hundredth.
A) 157.08 ft2
B) 162.8 ft2
C) 257.08 ft2
D) 414.16 ft2






A sphere of diameter D inches is cut by a plane which passes through its center. Find the area of the cross-section, leaving the answer in terms of π.A)πD4 in2B)πD2 in2C)πD24 in2D)πD22 in22)

 Find the area of the figure shown in the diagram to the nearest hundredth.
A)16.00 m2B)28.57 m2C)41.13 m2D)49.12 m2

Find the area of the figure shown in the diagram to the nearest hundredth A 15708 ft2 B 1628 ft2 C 25708 ft2 D 41416 ft2A sphere of diameter D inches is cut by class=
Find the area of the figure shown in the diagram to the nearest hundredth A 15708 ft2 B 1628 ft2 C 25708 ft2 D 41416 ft2A sphere of diameter D inches is cut by class=

Respuesta :

area of square=10*10=100
area of circle=pi*d^2/4
                     =pi*100/4
                      =25*pi
as we have 4 semi circles means 2 full circles
so tatal area=100+50*pi=257 feet^2
so opton c

Answer:

Figure 1: The figure has a square and 2 circles. So, to find he area of the figure we will add the area of square plus area of 2 circles.

Now, the side length of square is = 10 feet

Area = 10*10=100 square feet

The side of square acts as a diameter, so radius will be = 10/2 = 5 feet

Area of circle = [tex]\pi r^{2}[/tex]

= [tex]3.143*5*5=78.575[/tex]

Area of 2 circles will be = 78.575*2 = 157.15

So, area of the figure = 100+157.15 = 257.15 square feet.

So, option C is correct.

2. When a sphere is cut by a plane which passes through the center, the cross section is a circle with the same diameter of the sphere.

So, diameter is D. Then radius = D/2

Area of circle = [tex]\pi (\frac{D}{2})^{2}[/tex] or [tex]\pi \frac{D^{2} }{4}[/tex] square inches. The given options are not clear(May be 3rd one). But this is the correct answer.

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