Aqueous calcium bromide was mixed with aqueous gold(i perchlorate, and a crystallized gold(i bromide product was formed. consider the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.

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20-02-2017
Chemistry

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Aqueous calcium bromide was mixed with aqueous gold(i perchlorate, and a crystallized gold(i bromide product was formed. consider the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.

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MissPhiladelphia MissPhiladelphia · Answer 1 · 2017-02-28T06:18:50+01:00

Calcium bromide is CaBr2
Gold(I) perchlorate is AuClO4
Crystallized gold(I) bromide would be AuBr(s). beginning with those, your equation would be:
CaBr2(aq) + AuClO4(aq) --> AuBr(s)
Now, the other product would be calcium perchlorate that would remain soluble. Since perchlorate has a -1 charge, you will need 2 of that ion to balance a calcium ion. Also, since you have 2 Br- ions on the left, you will need 2 AuBr(s) on the right. All of that leads to:

CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)

lceget22 lceget22 · Answer 2 · 2020-08-11T16:40:51+02:00

lceget22 lceget22

11-08-2020

Answer:

CaBr2(aq) + 2 AuClO4(aq) --> 2 AuBr(s) + Ca(ClO4)2(aq)

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